Optimal. Leaf size=240 \[ \frac{\left (d+e x^2\right )^5 \left (a+b \tan ^{-1}(c x)\right )}{10 e^2}-\frac{d \left (d+e x^2\right )^4 \left (a+b \tan ^{-1}(c x)\right )}{8 e^2}-\frac{b e x^5 \left (20 c^4 d^2-15 c^2 d e+4 e^2\right )}{200 c^5}-\frac{b x^3 \left (-20 c^4 d^2 e+10 c^6 d^3+15 c^2 d e^2-4 e^3\right )}{120 c^7}+\frac{b x \left (-20 c^4 d^2 e+10 c^6 d^3+15 c^2 d e^2-4 e^3\right )}{40 c^9}-\frac{b e^2 x^7 \left (15 c^2 d-4 e\right )}{280 c^3}+\frac{b \left (c^2 d-e\right )^4 \left (c^2 d+4 e\right ) \tan ^{-1}(c x)}{40 c^{10} e^2}-\frac{b e^3 x^9}{90 c} \]
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Rubi [A] time = 0.458801, antiderivative size = 285, normalized size of antiderivative = 1.19, number of steps used = 8, number of rules used = 7, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {266, 43, 4976, 12, 528, 388, 203} \[ \frac{\left (d+e x^2\right )^5 \left (a+b \tan ^{-1}(c x)\right )}{10 e^2}-\frac{d \left (d+e x^2\right )^4 \left (a+b \tan ^{-1}(c x)\right )}{8 e^2}-\frac{b x \left (25 c^4 d^2-135 c^2 d e+84 e^2\right ) \left (d+e x^2\right )^2}{4200 c^5 e}+\frac{b x \left (750 c^4 d^2 e+5 c^6 d^3-1071 c^2 d e^2+420 e^3\right ) \left (d+e x^2\right )}{12600 c^7 e}+\frac{b x \left (-4977 c^4 d^2 e^2+1815 c^6 d^3 e+325 c^8 d^4+4305 c^2 d e^3-1260 e^4\right )}{12600 c^9 e}+\frac{b \left (c^2 d-e\right )^4 \left (c^2 d+4 e\right ) \tan ^{-1}(c x)}{40 c^{10} e^2}-\frac{b x \left (23 c^2 d-36 e\right ) \left (d+e x^2\right )^3}{2520 c^3 e}-\frac{b x \left (d+e x^2\right )^4}{90 c e} \]
Antiderivative was successfully verified.
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Rule 266
Rule 43
Rule 4976
Rule 12
Rule 528
Rule 388
Rule 203
Rubi steps
\begin{align*} \int x^3 \left (d+e x^2\right )^3 \left (a+b \tan ^{-1}(c x)\right ) \, dx &=-\frac{d \left (d+e x^2\right )^4 \left (a+b \tan ^{-1}(c x)\right )}{8 e^2}+\frac{\left (d+e x^2\right )^5 \left (a+b \tan ^{-1}(c x)\right )}{10 e^2}-(b c) \int \frac{\left (d+e x^2\right )^4 \left (-d+4 e x^2\right )}{40 e^2 \left (1+c^2 x^2\right )} \, dx\\ &=-\frac{d \left (d+e x^2\right )^4 \left (a+b \tan ^{-1}(c x)\right )}{8 e^2}+\frac{\left (d+e x^2\right )^5 \left (a+b \tan ^{-1}(c x)\right )}{10 e^2}-\frac{(b c) \int \frac{\left (d+e x^2\right )^4 \left (-d+4 e x^2\right )}{1+c^2 x^2} \, dx}{40 e^2}\\ &=-\frac{b x \left (d+e x^2\right )^4}{90 c e}-\frac{d \left (d+e x^2\right )^4 \left (a+b \tan ^{-1}(c x)\right )}{8 e^2}+\frac{\left (d+e x^2\right )^5 \left (a+b \tan ^{-1}(c x)\right )}{10 e^2}-\frac{b \int \frac{\left (d+e x^2\right )^3 \left (-d \left (9 c^2 d+4 e\right )+\left (23 c^2 d-36 e\right ) e x^2\right )}{1+c^2 x^2} \, dx}{360 c e^2}\\ &=-\frac{b \left (23 c^2 d-36 e\right ) x \left (d+e x^2\right )^3}{2520 c^3 e}-\frac{b x \left (d+e x^2\right )^4}{90 c e}-\frac{d \left (d+e x^2\right )^4 \left (a+b \tan ^{-1}(c x)\right )}{8 e^2}+\frac{\left (d+e x^2\right )^5 \left (a+b \tan ^{-1}(c x)\right )}{10 e^2}-\frac{b \int \frac{\left (d+e x^2\right )^2 \left (-3 d \left (21 c^4 d^2+17 c^2 d e-12 e^2\right )+3 e \left (25 c^4 d^2-135 c^2 d e+84 e^2\right ) x^2\right )}{1+c^2 x^2} \, dx}{2520 c^3 e^2}\\ &=-\frac{b \left (25 c^4 d^2-135 c^2 d e+84 e^2\right ) x \left (d+e x^2\right )^2}{4200 c^5 e}-\frac{b \left (23 c^2 d-36 e\right ) x \left (d+e x^2\right )^3}{2520 c^3 e}-\frac{b x \left (d+e x^2\right )^4}{90 c e}-\frac{d \left (d+e x^2\right )^4 \left (a+b \tan ^{-1}(c x)\right )}{8 e^2}+\frac{\left (d+e x^2\right )^5 \left (a+b \tan ^{-1}(c x)\right )}{10 e^2}-\frac{b \int \frac{\left (d+e x^2\right ) \left (-3 d \left (105 c^6 d^3+110 c^4 d^2 e-195 c^2 d e^2+84 e^3\right )-3 e \left (5 c^6 d^3+750 c^4 d^2 e-1071 c^2 d e^2+420 e^3\right ) x^2\right )}{1+c^2 x^2} \, dx}{12600 c^5 e^2}\\ &=\frac{b \left (5 c^6 d^3+750 c^4 d^2 e-1071 c^2 d e^2+420 e^3\right ) x \left (d+e x^2\right )}{12600 c^7 e}-\frac{b \left (25 c^4 d^2-135 c^2 d e+84 e^2\right ) x \left (d+e x^2\right )^2}{4200 c^5 e}-\frac{b \left (23 c^2 d-36 e\right ) x \left (d+e x^2\right )^3}{2520 c^3 e}-\frac{b x \left (d+e x^2\right )^4}{90 c e}-\frac{d \left (d+e x^2\right )^4 \left (a+b \tan ^{-1}(c x)\right )}{8 e^2}+\frac{\left (d+e x^2\right )^5 \left (a+b \tan ^{-1}(c x)\right )}{10 e^2}-\frac{b \int \frac{-3 d \left (315 c^8 d^4+325 c^6 d^3 e-1335 c^4 d^2 e^2+1323 c^2 d e^3-420 e^4\right )-3 e \left (325 c^8 d^4+1815 c^6 d^3 e-4977 c^4 d^2 e^2+4305 c^2 d e^3-1260 e^4\right ) x^2}{1+c^2 x^2} \, dx}{37800 c^7 e^2}\\ &=\frac{b \left (325 c^8 d^4+1815 c^6 d^3 e-4977 c^4 d^2 e^2+4305 c^2 d e^3-1260 e^4\right ) x}{12600 c^9 e}+\frac{b \left (5 c^6 d^3+750 c^4 d^2 e-1071 c^2 d e^2+420 e^3\right ) x \left (d+e x^2\right )}{12600 c^7 e}-\frac{b \left (25 c^4 d^2-135 c^2 d e+84 e^2\right ) x \left (d+e x^2\right )^2}{4200 c^5 e}-\frac{b \left (23 c^2 d-36 e\right ) x \left (d+e x^2\right )^3}{2520 c^3 e}-\frac{b x \left (d+e x^2\right )^4}{90 c e}-\frac{d \left (d+e x^2\right )^4 \left (a+b \tan ^{-1}(c x)\right )}{8 e^2}+\frac{\left (d+e x^2\right )^5 \left (a+b \tan ^{-1}(c x)\right )}{10 e^2}+\frac{\left (b \left (c^2 d-e\right )^4 \left (c^2 d+4 e\right )\right ) \int \frac{1}{1+c^2 x^2} \, dx}{40 c^9 e^2}\\ &=\frac{b \left (325 c^8 d^4+1815 c^6 d^3 e-4977 c^4 d^2 e^2+4305 c^2 d e^3-1260 e^4\right ) x}{12600 c^9 e}+\frac{b \left (5 c^6 d^3+750 c^4 d^2 e-1071 c^2 d e^2+420 e^3\right ) x \left (d+e x^2\right )}{12600 c^7 e}-\frac{b \left (25 c^4 d^2-135 c^2 d e+84 e^2\right ) x \left (d+e x^2\right )^2}{4200 c^5 e}-\frac{b \left (23 c^2 d-36 e\right ) x \left (d+e x^2\right )^3}{2520 c^3 e}-\frac{b x \left (d+e x^2\right )^4}{90 c e}+\frac{b \left (c^2 d-e\right )^4 \left (c^2 d+4 e\right ) \tan ^{-1}(c x)}{40 c^{10} e^2}-\frac{d \left (d+e x^2\right )^4 \left (a+b \tan ^{-1}(c x)\right )}{8 e^2}+\frac{\left (d+e x^2\right )^5 \left (a+b \tan ^{-1}(c x)\right )}{10 e^2}\\ \end{align*}
Mathematica [A] time = 0.226935, size = 262, normalized size = 1.09 \[ \frac{c x \left (315 a c^9 x^3 \left (20 d^2 e x^2+10 d^3+15 d e^2 x^4+4 e^3 x^6\right )-b \left (5 c^8 \left (252 d^2 e x^4+210 d^3 x^2+135 d e^2 x^6+28 e^3 x^8\right )-15 c^6 \left (140 d^2 e x^2+210 d^3+63 d e^2 x^4+12 e^3 x^6\right )+63 c^4 e \left (100 d^2+25 d e x^2+4 e^2 x^4\right )-105 c^2 e^2 \left (45 d+4 e x^2\right )+1260 e^3\right )\right )+315 b \tan ^{-1}(c x) \left (c^{10} x^4 \left (20 d^2 e x^2+10 d^3+15 d e^2 x^4+4 e^3 x^6\right )+20 c^4 d^2 e-10 c^6 d^3-15 c^2 d e^2+4 e^3\right )}{12600 c^{10}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.038, size = 315, normalized size = 1.3 \begin{align*} -{\frac{b{d}^{2}e{x}^{5}}{10\,c}}+{\frac{b{x}^{3}{d}^{2}e}{6\,{c}^{3}}}-{\frac{b{x}^{3}d{e}^{2}}{8\,{c}^{5}}}-{\frac{b{d}^{2}ex}{2\,{c}^{5}}}-{\frac{3\,\arctan \left ( cx \right ) bd{e}^{2}}{8\,{c}^{8}}}+{\frac{b{d}^{2}\arctan \left ( cx \right ) e}{2\,{c}^{6}}}+{\frac{3\,b\arctan \left ( cx \right ) d{e}^{2}{x}^{8}}{8}}+{\frac{b\arctan \left ( cx \right ){d}^{2}e{x}^{6}}{2}}-{\frac{3\,bd{e}^{2}{x}^{7}}{56\,c}}+{\frac{3\,bd{e}^{2}x}{8\,{c}^{7}}}+{\frac{3\,b{x}^{5}d{e}^{2}}{40\,{c}^{3}}}+{\frac{a{e}^{3}{x}^{10}}{10}}+{\frac{a{x}^{4}{d}^{3}}{4}}-{\frac{b{d}^{3}\arctan \left ( cx \right ) }{4\,{c}^{4}}}+{\frac{b{x}^{7}{e}^{3}}{70\,{c}^{3}}}+{\frac{b\arctan \left ( cx \right ){x}^{4}{d}^{3}}{4}}+{\frac{b\arctan \left ( cx \right ){e}^{3}{x}^{10}}{10}}-{\frac{b{e}^{3}x}{10\,{c}^{9}}}+{\frac{b{e}^{3}{x}^{3}}{30\,{c}^{7}}}-{\frac{b{x}^{5}{e}^{3}}{50\,{c}^{5}}}+{\frac{a{d}^{2}e{x}^{6}}{2}}+{\frac{3\,ad{e}^{2}{x}^{8}}{8}}+{\frac{b\arctan \left ( cx \right ){e}^{3}}{10\,{c}^{10}}}+{\frac{b{d}^{3}x}{4\,{c}^{3}}}-{\frac{b{d}^{3}{x}^{3}}{12\,c}}-{\frac{b{e}^{3}{x}^{9}}{90\,c}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.48413, size = 362, normalized size = 1.51 \begin{align*} \frac{1}{10} \, a e^{3} x^{10} + \frac{3}{8} \, a d e^{2} x^{8} + \frac{1}{2} \, a d^{2} e x^{6} + \frac{1}{4} \, a d^{3} x^{4} + \frac{1}{12} \,{\left (3 \, x^{4} \arctan \left (c x\right ) - c{\left (\frac{c^{2} x^{3} - 3 \, x}{c^{4}} + \frac{3 \, \arctan \left (c x\right )}{c^{5}}\right )}\right )} b d^{3} + \frac{1}{30} \,{\left (15 \, x^{6} \arctan \left (c x\right ) - c{\left (\frac{3 \, c^{4} x^{5} - 5 \, c^{2} x^{3} + 15 \, x}{c^{6}} - \frac{15 \, \arctan \left (c x\right )}{c^{7}}\right )}\right )} b d^{2} e + \frac{1}{280} \,{\left (105 \, x^{8} \arctan \left (c x\right ) - c{\left (\frac{15 \, c^{6} x^{7} - 21 \, c^{4} x^{5} + 35 \, c^{2} x^{3} - 105 \, x}{c^{8}} + \frac{105 \, \arctan \left (c x\right )}{c^{9}}\right )}\right )} b d e^{2} + \frac{1}{3150} \,{\left (315 \, x^{10} \arctan \left (c x\right ) - c{\left (\frac{35 \, c^{8} x^{9} - 45 \, c^{6} x^{7} + 63 \, c^{4} x^{5} - 105 \, c^{2} x^{3} + 315 \, x}{c^{10}} - \frac{315 \, \arctan \left (c x\right )}{c^{11}}\right )}\right )} b e^{3} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.42384, size = 711, normalized size = 2.96 \begin{align*} \frac{1260 \, a c^{10} e^{3} x^{10} + 4725 \, a c^{10} d e^{2} x^{8} - 140 \, b c^{9} e^{3} x^{9} + 6300 \, a c^{10} d^{2} e x^{6} + 3150 \, a c^{10} d^{3} x^{4} - 45 \,{\left (15 \, b c^{9} d e^{2} - 4 \, b c^{7} e^{3}\right )} x^{7} - 63 \,{\left (20 \, b c^{9} d^{2} e - 15 \, b c^{7} d e^{2} + 4 \, b c^{5} e^{3}\right )} x^{5} - 105 \,{\left (10 \, b c^{9} d^{3} - 20 \, b c^{7} d^{2} e + 15 \, b c^{5} d e^{2} - 4 \, b c^{3} e^{3}\right )} x^{3} + 315 \,{\left (10 \, b c^{7} d^{3} - 20 \, b c^{5} d^{2} e + 15 \, b c^{3} d e^{2} - 4 \, b c e^{3}\right )} x + 315 \,{\left (4 \, b c^{10} e^{3} x^{10} + 15 \, b c^{10} d e^{2} x^{8} + 20 \, b c^{10} d^{2} e x^{6} + 10 \, b c^{10} d^{3} x^{4} - 10 \, b c^{6} d^{3} + 20 \, b c^{4} d^{2} e - 15 \, b c^{2} d e^{2} + 4 \, b e^{3}\right )} \arctan \left (c x\right )}{12600 \, c^{10}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 9.67284, size = 411, normalized size = 1.71 \begin{align*} \begin{cases} \frac{a d^{3} x^{4}}{4} + \frac{a d^{2} e x^{6}}{2} + \frac{3 a d e^{2} x^{8}}{8} + \frac{a e^{3} x^{10}}{10} + \frac{b d^{3} x^{4} \operatorname{atan}{\left (c x \right )}}{4} + \frac{b d^{2} e x^{6} \operatorname{atan}{\left (c x \right )}}{2} + \frac{3 b d e^{2} x^{8} \operatorname{atan}{\left (c x \right )}}{8} + \frac{b e^{3} x^{10} \operatorname{atan}{\left (c x \right )}}{10} - \frac{b d^{3} x^{3}}{12 c} - \frac{b d^{2} e x^{5}}{10 c} - \frac{3 b d e^{2} x^{7}}{56 c} - \frac{b e^{3} x^{9}}{90 c} + \frac{b d^{3} x}{4 c^{3}} + \frac{b d^{2} e x^{3}}{6 c^{3}} + \frac{3 b d e^{2} x^{5}}{40 c^{3}} + \frac{b e^{3} x^{7}}{70 c^{3}} - \frac{b d^{3} \operatorname{atan}{\left (c x \right )}}{4 c^{4}} - \frac{b d^{2} e x}{2 c^{5}} - \frac{b d e^{2} x^{3}}{8 c^{5}} - \frac{b e^{3} x^{5}}{50 c^{5}} + \frac{b d^{2} e \operatorname{atan}{\left (c x \right )}}{2 c^{6}} + \frac{3 b d e^{2} x}{8 c^{7}} + \frac{b e^{3} x^{3}}{30 c^{7}} - \frac{3 b d e^{2} \operatorname{atan}{\left (c x \right )}}{8 c^{8}} - \frac{b e^{3} x}{10 c^{9}} + \frac{b e^{3} \operatorname{atan}{\left (c x \right )}}{10 c^{10}} & \text{for}\: c \neq 0 \\a \left (\frac{d^{3} x^{4}}{4} + \frac{d^{2} e x^{6}}{2} + \frac{3 d e^{2} x^{8}}{8} + \frac{e^{3} x^{10}}{10}\right ) & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.64996, size = 479, normalized size = 2. \begin{align*} \frac{1260 \, b c^{10} x^{10} \arctan \left (c x\right ) e^{3} + 1260 \, a c^{10} x^{10} e^{3} + 4725 \, b c^{10} d x^{8} \arctan \left (c x\right ) e^{2} + 4725 \, a c^{10} d x^{8} e^{2} + 6300 \, b c^{10} d^{2} x^{6} \arctan \left (c x\right ) e - 140 \, b c^{9} x^{9} e^{3} + 6300 \, a c^{10} d^{2} x^{6} e + 3150 \, b c^{10} d^{3} x^{4} \arctan \left (c x\right ) - 675 \, b c^{9} d x^{7} e^{2} + 3150 \, a c^{10} d^{3} x^{4} - 1260 \, b c^{9} d^{2} x^{5} e - 1050 \, b c^{9} d^{3} x^{3} + 180 \, b c^{7} x^{7} e^{3} + 945 \, b c^{7} d x^{5} e^{2} + 2100 \, b c^{7} d^{2} x^{3} e + 3150 \, b c^{7} d^{3} x - 252 \, b c^{5} x^{5} e^{3} - 3150 \, b c^{6} d^{3} \arctan \left (c x\right ) - 1575 \, b c^{5} d x^{3} e^{2} - 6300 \, \pi b c^{4} d^{2} e \mathrm{sgn}\left (c\right ) \mathrm{sgn}\left (x\right ) - 6300 \, b c^{5} d^{2} x e + 6300 \, b c^{4} d^{2} \arctan \left (c x\right ) e + 420 \, b c^{3} x^{3} e^{3} + 4725 \, b c^{3} d x e^{2} - 4725 \, b c^{2} d \arctan \left (c x\right ) e^{2} - 1260 \, \pi b e^{3} \mathrm{sgn}\left (c\right ) \mathrm{sgn}\left (x\right ) - 1260 \, b c x e^{3} + 1260 \, b \arctan \left (c x\right ) e^{3}}{12600 \, c^{10}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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